<TestItem CLASS="ssmc" METHOD="list">
<Stimulus TYPE="text">
  <TABLE>
	<TR>
		<TD class="underLine"><Emphasis>A</Emphasis></TD>
		<TD class="underLine"><Emphasis>B</Emphasis></TD>
	</TR>
	<TR>
		<TD>2</TD>
		<TD>5</TD>
	</TR>
	<TR>
		<TD>3</TD>
		<TD>7</TD>
	</TR>
	<TR>
		<TD>4</TD>
		<TD>9</TD>
	</TR>
	<TR>
		<TD>5</TD>
		<TD>11</TD>
	</TR>
	<TR>
		<TD><Emphasis>...</Emphasis></TD>
		<TD><Emphasis>...</Emphasis></TD>
	</TR>
	<TR>
		<TD>7</TD>
		<TD><Emphasis>?</Emphasis></TD>
	</TR>
  </TABLE>
</Stimulus>
<Stem>
  <Paragraph><Sentence>
  If the pattern shown in the table on the left were continued, what number 
  would appear in the box at the bottom of column B, where A is 7?
  </Sentence></Paragraph>

</Stem>
<Distractor_list>
  <Distractor><Paragraph><Sentence>19</Sentence></Paragraph></Distractor>
  <Distractor><Paragraph><Sentence>13</Sentence></Paragraph></Distractor>
  <Distractor><Paragraph><Sentence>18</Sentence></Paragraph></Distractor>
  <Distractor><Paragraph><Sentence>12</Sentence></Paragraph></Distractor>
  <Distractor><Paragraph><Sentence>15</Sentence></Paragraph></Distractor>
</Distractor_list>
<key TYPE="SSMC">
    <response  SCORE="0" EVIDENCEVAL="0">
        <observable>1</observable>
        <feedback TYPE="Student">Sorry, that's not right.  In problems like this, you need to find
                                 the common difference and add it to the last given number the right
                                 number of times.  The common difference here is 2, and the correct
                                 answer is 15.</feedback>
        <feedback TYPE="Teacher">Could be that the student added wrong.</feedback>
    </response>
    <response  SCORE="0" EVIDENCEVAL="0">
        <observable>2</observable>
        <feedback TYPE="Student">Good try, but not quite.  It looks like you added the correct common 
                                 difference (2) to the last given item only one time.  The problem asked
                                 for the value of B when A is 7.  The correct answer is 15. </feedback>
        <feedback TYPE="Teacher">Could have added 2 to the "last number" ignoring the hiatus.</feedback>
    </response>
    <response  SCORE="0" EVIDENCEVAL="0">
        <observable>3</observable>
        <feedback TYPE="Student">Sorry, that's not right. In problems like this, you need to find
                                 the common difference and add it to the last given number the right
                                 number of times.  The common difference here is 2, and the correct
                                 answer is 15. </feedback>
        <feedback TYPE="Teacher">Seems to have added 11 to 7.</feedback>
    </response>
    <response  SCORE="0" EVIDENCEVAL="0">
        <observable>4</observable>
        <feedback TYPE="Student">Sorry, that's not right.  In problems like this, you need to find
                                 the common difference and add it to the last given number the right
                                 number of times.  The common difference here is 2, and the correct
                                 answer is 15.</feedback>
        <feedback TYPE="Teacher">It's possible that the student just added 1 to 11.</feedback>
    </response>
    <response  SCORE="1" EVIDENCEVAL="1">
        <observable>5</observable>
        <feedback TYPE="Student">Right!</feedback>
        <feedback TYPE="Teacher">The student got this item correct.</feedback>
    </response>
</key>	
<Metadata>
    <AeL ItemNode="tTableExtendArithmetic1a" Difficulty="1">
        <PMNode LINK="true">TableArithmetic</PMNode>
        <PMNode>ExtendArithmetic</PMNode>
    </AeL>
</Metadata>
 
</TestItem>
